document.write( "Question 214699: A car traveled at an average rate of 40 miles per hour and then reduced it's average rate to 30 miles per hour for the rest of the trip. If the 180 mile trip took 5 hours, determine how long the car traveled at each rate. \n" ); document.write( "
Algebra.Com's Answer #162146 by ankor@dixie-net.com(22740)\"\" \"About 
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A car traveled at an average rate of 40 miles per hour;
\n" ); document.write( "then reduced it's average rate to 30 miles per hour for the rest of the trip.
\n" ); document.write( "If the 180 mile trip took 5 hours, determine how long the car traveled at each rate.
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\n" ); document.write( "Let t = time at 40 mph
\n" ); document.write( "Total time was given as 5 hr, therefore
\n" ); document.write( "(5-t) = time at 30 mph
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\n" ); document.write( "Write a distance equation: dist = speed * time
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\n" ); document.write( "40mph dist + 30mph dist = 180 mi
\n" ); document.write( "40t + 30(5-t) = 180
\n" ); document.write( "40t + 150 - 30t = 180
\n" ); document.write( "40t - 30t = 180 - 150
\n" ); document.write( "10t = 30
\n" ); document.write( "t = 3 hrs at 40 mph
\n" ); document.write( "and
\n" ); document.write( "5 - 3 = 2 hrs at 30 mph
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\n" ); document.write( ":
\n" ); document.write( "Check solutions by finding the dist at each speed
\n" ); document.write( "40(3) = 120 mi
\n" ); document.write( "30(2) = 60 mi
\n" ); document.write( "total = 180 mi
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