document.write( "Question 214172: If one side of a square is increased by 8cm and an adjacent side decreased by 2cm, a rectangle is formed whose perimeter is 40cm. Find the length of a side of the square. \n" ); document.write( "
Algebra.Com's Answer #162139 by Earlsdon(6294)\"\" \"About 
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Let the length of a side of the square = s, then the perimeter is expressed by:
\n" ); document.write( "\"P+=+2%28s%2Bs%29\" Increase one side by 8cm. to get (s+8)cm. and decrease an adjacent side by 2cm. to get (s-2)cm.. The resulting perimeter (P) is 40cm.
\n" ); document.write( "\"40+=+2%28%28s%2B8%29%2B%28s-2%29%29\" Divide both sides by 2.
\n" ); document.write( "\"20+=+s%2B8%2Bs-2\" Simplify.
\n" ); document.write( "\"20+=+2s%2B6\" Subtract 6 from both sdes.
\n" ); document.write( "\"14+=+2s\" Divide both sides by 2.
\n" ); document.write( "\"7++=+s\"
\n" ); document.write( "The length of a side of the square is 7cm.
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