document.write( "Question 214234This question is from textbook
\n" ); document.write( ": The Gazette's profit is $20 per year for each of its 3,000 subscribers. Management estimates that the profit per subscriber will increase by 1 cent
\n" ); document.write( "for each additional subscriber over the current 3,000. How many subscribers will bring a total profit of 120,000?
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Algebra.Com's Answer #162099 by josmiceli(19441)\"\" \"About 
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Let \"s\"= the number of subscribers over 3000 that will bring
\n" ); document.write( "Let \"P\" = yearly profit
\n" ); document.write( "a profit of $120,000
\n" ); document.write( "P= 20*3000 + 20.01s
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\n" ); document.write( "given:
\n" ); document.write( "\"P+=+120000\"
\n" ); document.write( "\"120000+=+60000+%2B+20.01s\"
\n" ); document.write( "\"20.01s+=+60000\"
\n" ); document.write( "\"s+=+2998.5\"
\n" ); document.write( "There has to be 2999 new subscribers
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