document.write( "Question 214239This question is from textbook
\n" ); document.write( ": The frame around the picture in the illustration has a constant width. how wide is the frame if the area equals the area of the picture\r
\n" ); document.write( "\n" ); document.write( " the illustration is a square inside a squre. the frame
\n" ); document.write( " with a width of 12 inches and a hight of 10 inches \r
\n" ); document.write( "\n" ); document.write( "I hope thats enough info 2 help me
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Algebra.Com's Answer #162090 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
The frame around the picture in the illustration has a constant width. how wide is the frame if the area equals the area of the picture
\n" ); document.write( "the illustration is a square inside a squre. the frame
\n" ); document.write( "with a width of 12 inches and a hight of 10 inches
\n" ); document.write( ".
\n" ); document.write( "Draw a diagram of the problem, label all the information given it'll help you see the solution.
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\n" ); document.write( "Let w = width of frame
\n" ); document.write( "then measure of picture is:
\n" ); document.write( "12-2w = width of picture
\n" ); document.write( "10-2w = length of picture
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\n" ); document.write( "Area of picture is (length times width):
\n" ); document.write( "(12-2w)(10-2w)
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\n" ); document.write( "Area of frame:
\n" ); document.write( "2(10w) + 2w(12-2w)
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\n" ); document.write( "Setting them equal\":
\n" ); document.write( "(12-2w)(10-2w) = 2(10w) + 2w(12-2w)
\n" ); document.write( "120-24w-20w+4w^2 = 20w + 24w - 4w^2
\n" ); document.write( "120-44w+4w^2 = 44w - 4w^2
\n" ); document.write( "8w^2+120-44w = 44w
\n" ); document.write( "8w^2-88w+120 = 0
\n" ); document.write( "w^2-11w+15 = 0
\n" ); document.write( "Using the quadratic equation we get two solutions:
\n" ); document.write( "w={9.40512483795333, 1.59487516204667}
\n" ); document.write( "It wouldn't make sense to have a 9+ inch width frame so the answer MUST be:
\n" ); document.write( "w = 1.595 inches (width of frame)
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\n" ); document.write( "Details of the quadratic equation to follow:\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aw%5E2%2Bbw%2Bc=0\" (in our case \"1w%5E2%2B-11w%2B15+=+0\") has the following solutons:
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\n" ); document.write( " \"w%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-11%29%5E2-4%2A1%2A15=61\".
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\n" ); document.write( " Discriminant d=61 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--11%2B-sqrt%28+61+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"w%5B1%5D+=+%28-%28-11%29%2Bsqrt%28+61+%29%29%2F2%5C1+=+9.40512483795333\"
\n" ); document.write( " \"w%5B2%5D+=+%28-%28-11%29-sqrt%28+61+%29%29%2F2%5C1+=+1.59487516204667\"
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\n" ); document.write( " Quadratic expression \"1w%5E2%2B-11w%2B15\" can be factored:
\n" ); document.write( " \"1w%5E2%2B-11w%2B15+=+1%28w-9.40512483795333%29%2A%28w-1.59487516204667%29\"
\n" ); document.write( " Again, the answer is: 9.40512483795333, 1.59487516204667.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-11%2Ax%2B15+%29\"

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