document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29374>Question 29374</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given the cost function, C(x), and the revenue function, R(x), find the number of units x that must be sold to break even?\r<BR>\n" );
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document.write( "C(x)=9000x + 45,000<BR>\n" );
document.write( "R(x)=12,000x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16204 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16204\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if you wanted the values for C(x) and R(x) to equal the same, then you would combine\r<BR>\n" );
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document.write( "R(x)=12,000x<BR>\n" );
document.write( "C(x)=(-1)9000x + (-1)45,000 --multiply by (-1) and (-1) to get 1 on one side<BR>\n" );
document.write( "C(x)=-9,000x-45,000<BR>\n" );
document.write( "3,000x-45,000=0 --combine<BR>\n" );
document.write( "3000x=45000 --add 45000<BR>\n" );
document.write( "x=15 --divide by 3000 </SPAN>\n" );
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