document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=214487>Question 214487</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find An Equation Of The Line Perpendicular To 3x-2y = 6, And Passing Through The Point (7,2)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #162027 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=162027\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x-2y = 6, And Passing Through The Point (7,2)?<BR>\n" );
document.write( "-2Y=-3X+6<BR>\n" );
document.write( "Y=-3X/-2+6/-2<BR>\n" );
document.write( "Y=3X/2-3 (RED LINE) WITH A SLOPE=3/2.<BR>\n" );
document.write( "A PERPENDICULAR LINE HAS A SLOPE=-2/3<BR>\n" );
document.write( "2=-2/3*7+b<BR>\n" );
document.write( "2=-14/3+b<BR>\n" );
document.write( "b=2+14/3<BR>\n" );
document.write( "b=6/3+14/3<BR>\n" );
document.write( "b=20/3 the y intercept<BR>\n" );
document.write( "Y=-2x/3+20/3 is this perpendicular line equation. (green line).<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+3x%2F2+-3%2C+-2x%2F3+%2B20%2F3%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+3x%2F2+-3%2C+-2x%2F3+%2B20%2F3%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > (graph 300x300 pixels, x from -10 to 10, y from -10 to 10, of TWO functions 3x/2 -3 and -2x/3 +20/3).   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );