document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=214485>Question 214485</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This is NOT from a text book.  <BR>\n" );
document.write( "The perimeter of one square is 36 inches more than the perimeter of a second square, and the area of the first square is 243 square inches more than the area of the second square.  Find the area of the larger square.\r<BR>\n" );
document.write( "\n" );
document.write( "My work so far:<BR>\n" );
document.write( "Square #1 Perimeter=4s+36  Area=s^2+243<BR>\n" );
document.write( "Square #2 Perimeter= 4s   Area=s^2\r<BR>\n" );
document.write( "\n" );
document.write( "I am unsure of how to set up the equation. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #162012 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=162012\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sq#1 ___ side length = perimeter / 4 = s+9 ___ area = (side length)^2 = (s+9)^2 = s^2 + 243\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "s^2 + 18s + 81 = s^2 + 243\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "18s = 162 ___ s = 9\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "A = 9^2 + 243 = 324 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );