document.write( "Question 214474: If $1,000 is invested at 4% interest, how much money must be invested at 11% interest so that the total return for both investments averages 10%? \n" ); document.write( "
Algebra.Com's Answer #162003 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
1,000*.04+.11x=.10(1000+x)
\n" ); document.write( "40+.11x=100+.10x
\n" ); document.write( ".11x-.10x=100-40
\n" ); document.write( ".-1x=60
\n" ); document.write( "x=60/.01
\n" ); document.write( "x=$6000 is the amount invested @ 11%.
\n" ); document.write( "Proof:
\n" ); document.write( "1000*.04+.11*6000=.10(1000+6000)
\n" ); document.write( "40+660=.10*7000
\n" ); document.write( "700=700
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