document.write( "Question 366: Can you help me with dividing polynomials? Here's the equation:\r
\n" );
document.write( "\n" );
document.write( "2x^3 - 3x^2 + 4x - 21 / 2x + 1 \n" );
document.write( "
Algebra.Com's Answer #162 by ashipm01(26)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "First you would take the 2x and see how many times that will go into 2x^3. Since it goes into 2x^3 x^2 times you multiply the 1 by x^2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now you should have (-4x^2+4X-21) as your divisor since you subtract the x^2 from the -3x^2 and you subtract the 2x^3 from the 2x^3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your current answer is x^2 after the first step.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now you do the same process. You take the 2x and see how many times it will divide into -4x^2 which is -2x times. So now you multiply the 1 by 2x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You then add the 4x^2 that you got when you multiply -2x *2x (you add it because you invert the sign so you can cancel the terms out) to -4x^2 which yields 0. You then multiply 1 * -2x and switch it from negative to positive and add that to the 4x to get 6x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your current answer should now be x^2 - 2x after the second step.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Next you take and see how many times 2x will go into 6x which is 3 times. Now you multiply 1 * 3 and invert the sign to get -3. Then you cancel out the 6x and you subtract 3 from -21 to get -24.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your current answer now should be x^2 - 2x +3 after the third step.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Finally you add the remainder which is -24 and divide it by the divisor (2x+1) to get a final answer of:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I hope this helps, \n" ); document.write( "Alex \n" ); document.write( " |