document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=214441>Question 214441</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a ball is kicked into the air and follows the path described by <BR>\n" );
document.write( "h(t)-4.9t^2+6t+0.6. where t is the time in seconds and h is the height in meters abouve the ground. Detrmine the maximum height of the ball to the nearest tenth of a meter.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #161988 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=161988\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> h(t) = -4.9t^2+6t+0.6<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Because of the negative coefficient associated with the t^2, we know that it is a parabola cup down.  This means that if we find the \"vertex\" we will have the maximum.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "The \"axis of symmetry\" is at:<BR>\n" );
document.write( "-b/(2a)<BR>\n" );
document.write( "= -6/(2*(-4.9))<BR>\n" );
document.write( "= -6/(2*(-4.9))<BR>\n" );
document.write( "= 0.612 seconds<BR>\n" );
document.write( "This is the time it takes to reach the peak.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "To find the height, plug the above back into:<BR>\n" );
document.write( "h(t) = -4.9t^2+6t+0.6<BR>\n" );
document.write( "h(0.612) = -4.9(0.612)^2+6(0.612)+0.6<BR>\n" );
document.write( "h(0.612) = 2.4 meters<BR>\n" );
document.write( " </SPAN>\n" );
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