document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=214376>Question 214376</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve this problem by substitution?\r<BR>\n" );
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document.write( "   2x+y=0\r<BR>\n" );
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document.write( "   3x-2y=7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #161917 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=161917\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do I solve this problem by substitution? <BR>\n" );
document.write( "2x+y=0 --> y = -2x <BR>\n" );
document.write( "3x-2y=7<BR>\n" );
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document.write( "Sub for y into 2nd eqn<BR>\n" );
document.write( "2x - 2(-2x) = 7<BR>\n" );
document.write( "7x = 7<BR>\n" );
document.write( "x = 1<BR>\n" );
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document.write( "y = -2\r<BR>\n" );
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document.write( " </SPAN>\n" );
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