document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=214297>Question 214297</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the measure of an angle whose supplement is 10 degrees more than twice its complement. Let 90 - x equal the degree measure of its complement and 180-x equal the degree of measure of its supplement.  how do I write the equation? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #161860 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=161860\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the measure of an angle whose supplement is 10 degrees more than twice its complement. Let 90 - x equal the degree measure of its complement and 180-x equal the degree of measure of its supplement. how do I write the equation?<BR>\n" );
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document.write( "Let the angle be \"x\"<BR>\n" );
document.write( "Supplement is \"180-x\"<BR>\n" );
document.write( "Complement is \"90-x\"<BR>\n" );
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document.write( "Equation: <BR>\n" );
document.write( "supplement = 2*complement + 10<BR>\n" );
document.write( "180-x = 2(90-x) + 10<BR>\n" );
document.write( "180-x = 180 - 2x + 10<BR>\n" );
document.write( "-x = -2x+10<BR>\n" );
document.write( "x = 10 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );