document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=214189>Question 214189</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve by substitution of linear equation?\r<BR>\n" );
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document.write( "  2x+y=9\r<BR>\n" );
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document.write( "  y=x-3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #161775 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=161775\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do you solve by substitution of linear equation? <BR>\n" );
document.write( "2x+y=9 <BR>\n" );
document.write( "y=x-3<BR>\n" );
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document.write( "The 2nd eqn has y isolated, so sub for y into the 1st eqn.<BR>\n" );
document.write( "2x+y=9<BR>\n" );
document.write( "2x + (x-3) = 9<BR>\n" );
document.write( "3x - 3 = 9<BR>\n" );
document.write( "3x = 12<BR>\n" );
document.write( "x = 4<BR>\n" );
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document.write( "y = x-3 = 4-3<BR>\n" );
document.write( "y = 1\r<BR>\n" );
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document.write( " </SPAN>\n" );
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