document.write( "Question 214187: How do I do this linear equation by solving by substitution?\r
\n" ); document.write( "\n" ); document.write( " y=x+3\r
\n" ); document.write( "\n" ); document.write( " x+y=5
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Algebra.Com's Answer #161774 by drj(1380)\"\" \"About 
You can put this solution on YOUR website!
\How do I do this linear equation by solving by substitution?\r
\n" ); document.write( "\n" ); document.write( " y=x+3\r
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\n" ); document.write( "\n" ); document.write( "The following steps will solve the system of linear equations by substitution:\r
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Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
\n" ); document.write( " \"+system%28+%0D%0A++++-1%5Cx+%2B+1%5Cy+=+3%2C%0D%0A++++1%5Cx+%2B+1%5Cy+=+5+%29%0D%0A++\"We'll use substitution. After moving 1*y to the right, we get:
\n" ); document.write( " \"-1%2Ax+=+3+-+1%2Ay\", or \"x+=+3%2F-1+-+1%2Ay%2F-1\". Substitute that
\n" ); document.write( " into another equation:
\n" ); document.write( " \"1%2A%283%2F-1+-+1%2Ay%2F-1%29+%2B+1%5Cy+=+5\" and simplify: So, we know that y=4. Since \"x+=+3%2F-1+-+1%2Ay%2F-1\", x=1.
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\n" ); document.write( " Answer: \"system%28+x=1%2C+y=4+%29\".
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\n" ); document.write( "\n" ); document.write( "The solutions are x=1 and y=4 or the point(1,4)\r
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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful. \r
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\n" ); document.write( "\n" ); document.write( "For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "And good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J
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