document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29365>Question 29365</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone help?\r<BR>\n" );
document.write( "\n" );
document.write( "-4=6(x-7)-3x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16177 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16177\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -4=6(x-7)-3x  ----(1)<BR>\n" );
document.write( "-4 = 6x-(6X7)-3x<BR>\n" );
document.write( "-4 = 6x-42-3x<BR>\n" );
document.write( "-4+42 = (6x-3x) (grouping like terms)(when side is changed then sign is changed)<BR>\n" );
document.write( "38 = 3x<BR>\n" );
document.write( "3x= 38<BR>\n" );
document.write( "x=38/3= 12 and 2/3<BR>\n" );
document.write( "Verification: RHS of (1) is <BR>\n" );
document.write( "6(x-7)-3x  = 6x-42-3x = 3x-42=38-42=-4 = LHS<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );