document.write( "Question 214165: 40 years ago i was 1/3 the age i will be in 4 years. How old am I? \n" ); document.write( "
Algebra.Com's Answer #161755 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
a = your age now
\n" ); document.write( ";
\n" ); document.write( "40 years ago i was 1/3 the age i will be in 4 years.
\n" ); document.write( "a - 40 = \"1%2F3\"(a+4)
\n" ); document.write( "Multiply both sides by 3, to get rid of the annoying fraction
\n" ); document.write( "3a - 120 = a + 4
\n" ); document.write( "3a - a = 4 + 120
\n" ); document.write( "2a = 124
\n" ); document.write( "a = 62 yr is your age now
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Check in the statement:
\n" ); document.write( "40 years ago i was 1/3 the age i will be in 4 years.
\n" ); document.write( "62 - 40 = \"1%2F3\"(62 + 4)
\n" ); document.write( "22 = \"1%2F3\"(66)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );