document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29359>Question 29359</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have not taken an Algebra class in 30 years,.. This has stumped me, even after referring to the text&#8230;<BR>\n" );
document.write( "Determine the equation of the following line. Write the answer in standard form using only integers  as coefficients.:<BR>\n" );
document.write( "&#8230;..The line through (-2,  4) that is perpendicular to the x-axis.\r<BR>\n" );
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document.write( "thanks in advance me </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16175 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16175\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Determine the equation of the following line. Write the answer in standard form using only integers  as coefficients.:<BR>\n" );
document.write( "&#8230;..The line through (-2,  4) that is perpendicular to the x-axis.\r<BR>\n" );
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document.write( "The line through (-2,  4) that is perpendicular to the x-axis.<BR>\n" );
document.write( "Any line perpendicular to the x-axis is parallel to the y-axis<BR>\n" );
document.write( "And any line parallel to the y -axis has its equation by<BR>\n" );
document.write( "x= k   ----(1)<BR>\n" );
document.write( "Now P(-2,4) is a point on this line<BR>\n" );
document.write( "Therefore putting x=-2 in (1)<BR>\n" );
document.write( "(-2) =k<BR>\n" );
document.write( "That is k=-2  (*)<BR>\n" );
document.write( "Putting (*) in (1)<BR>\n" );
document.write( "the required equation is <BR>\n" );
document.write( "x=-2<BR>\n" );
document.write( "which is a line parallel to the y-axis at a distance 2 units to the left of it\r<BR>\n" );
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document.write( "Note: In the above because you do not find any y in the equation (1) you did n't have the opportunity to supply y=4 in the equation to the line. This matter should not leave you perplexed. If that 4 is still disturbing,draw the co-ordinate axes of reference,draw a line parallel to the y-axis at a distance 2 units to the left of the origin.Mark the point P on this vertical line by going 4 units above the x-axis. You reach the point P(-2,4)<BR>\n" );
document.write( "Mark any other point or points on this vertical line. all of them will have their x-coordinate given by (-2). Hence the equation to that line is identified by x=-2<BR>\n" );
document.write( "Therefore the general rule of thumb is :<BR>\n" );
document.write( "Any line parallel to the x-axis will have its equation given by<BR>\n" );
document.write( "y= c<BR>\n" );
document.write( "where c is the distance between our line and the x-axis<BR>\n" );
document.write( "If c >0 that is if c is positive, then the line is above the x-axis<BR>\n" );
document.write( "If C <0 that is if c is negative,then the line is below the x-axis<BR>\n" );
document.write( "Any line parallel to the y-axis will have its equation given by<BR>\n" );
document.write( "x= k<BR>\n" );
document.write( "where k is the distance between our line and the y-axis<BR>\n" );
document.write( "If k >0 that is if k is positive, then the line is to the right of the y-axis<BR>\n" );
document.write( "If k <0 that is if k is negative,then the line is to the left of the y-axis\r<BR>\n" );
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document.write( "Note: If you had thought along the lines of slope and one point form of equation to the line there is no harm!<BR>\n" );
document.write( "Any line perpendicular to the x-axis makes an angle 90 degrees <BR>\n" );
document.write( "with the x-axis and has slope = tan(90)= infinity = (something)/0<BR>\n" );
document.write( "The slope and one point form of equation to a line is<BR>\n" );
document.write( "(y-y1)/(x-x1) = slope where P(x1,y1) is the given fixed point<BR>\n" );
document.write( "And here P(x1,y1)=P(-2,4)<BR>\n" );
document.write( "Therefore applying the above equation<BR>\n" );
document.write( "(y-4)/([x-(-2)] =(something)/0<BR>\n" );
document.write( "which implies the dr = 0 <BR>\n" );
document.write( "Therefore [x-(-2)] =0<BR>\n" );
document.write( "x+2 = 0<BR>\n" );
document.write( "That is x= -2  <BR>\n" );
document.write( "Note:(If a fraction is zero,then the nr =0 <BR>\n" );
document.write( "and if a fraction is infinity then the dr = 0) \r<BR>\n" );
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document.write( " </SPAN>\n" );
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