document.write( "Question 214154: Marilyn drove her car from Amirillo to Dallas at an average rate of 55 miles per hour and returned over icy roads averaging only 30 miles per hour. Find the time going and the time returning if the time returning was 4 hours more than the time going. \n" ); document.write( "
Algebra.Com's Answer #161749 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
write 1 equation for going
\n" ); document.write( "and another for returning
\n" ); document.write( "\"d%5B1%5D+=+r%5B1%5D%2At%5B1%5D\"
\n" ); document.write( "and
\n" ); document.write( "\"d%5B2%5D+=+r%5B2%5D%2At%5B2%5D\"
\n" ); document.write( "given:
\n" ); document.write( "\"r%5B1%5D+=+55\" mi/hr
\n" ); document.write( "\"r%5B2%5D+=+30\" mi/hr
\n" ); document.write( "\"t%5B2%5D+=+t%5B1%5D+%2B+4\" hrs
\n" ); document.write( "\"d%5B1%5D+=+d%5B2%5D\" (call it \"d\")
\n" ); document.write( "---------------------------------
\n" ); document.write( "Rewrite the equations
\n" ); document.write( "\"d+=+55t%5B1%5D\"
\n" ); document.write( "\"d+=+30%2A%28t%5B1%5D+%2B+4%29\"
\n" ); document.write( "\"55t%5B1%5D+=+30t%5B1%5D+%2B+120\"
\n" ); document.write( "\"25t%5B1%5D+=+120\"
\n" ); document.write( "\"t%5B1%5D+=+4.8\" hr
\n" ); document.write( "\"t%5B1%5D+%2B+4+=+8.8\" hr
\n" ); document.write( "The time going was 4.8 hrs and
\n" ); document.write( "the time returning was 8.8 hrs
\n" ); document.write( "check answer:
\n" ); document.write( "\"d+=+55t%5B1%5D\"
\n" ); document.write( "\"d+=+55%2A4.8\"
\n" ); document.write( "\"d+=+264\" mi
\n" ); document.write( "\"d+=+30%2A%28t%5B1%5D+%2B+4%29\"
\n" ); document.write( "\"d+=+30%2A8.8\"
\n" ); document.write( "\"d+=+264\" mi
\n" ); document.write( "OK
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