document.write( "Question 214139: two buses leave the same city at the same time moving in opposite directions. One travels at a rate of 5 miles per hour faster then the other bus. After 3 hours they are 375 miles apart. How far did each bus travel\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I think the equation I should use is D= RT but I dont get this question because I dont know the speed of both cars.
\n" ); document.write( "

Algebra.Com's Answer #161742 by drj(1380)\"\" \"About 
You can put this solution on YOUR website!
Two buses leave the same city at the same time moving in opposite directions. One travels at a rate of 5 miles per hour faster then the other bus. After 3 hours they are 375 miles apart. How far did each bus travel.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 1. Let x be the speed of one bus and let x+5 be the speed of the other bus.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 2. Distance = speed * time\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 3. Distance of one bus = 3x and Distance of other bus = 3(x+5).\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 4. Total Distance = Distance of one bus + Distance of other bus = 375 miles\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 5. Combine steps 2 and 3 to get 3x+3(x+5)=375 or 6x+15=375. Solving for x yields the following steps.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:

\n" ); document.write( "
\n" ); document.write( "

\n" ); document.write( " YOUR ANSWER\n" ); document.write( "


\n" ); document.write( "\n" ); document.write( "
    \n" ); document.write( "
  • This is an equation! Solutions: x=60.
  • \n" ); document.write( "
  • Graphical form: Equation \"6x%2B15=375\" was fully solved.
  • Text form: 6x+15=375 simplifies to 0=0
  • Cartoon (animation) form: \"simplify_cartoon%28+6x%2B15=375+%29\"
    For tutors: simplify_cartoon( 6x+15=375 )
  • \n" ); document.write( "
  • If you have a website, here's a link to this solution.
  • \n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

DETAILED EXPLANATION

\n" ); document.write( "
Look at \"6%2Ax%2B15=highlight_red%28+375+%29\".
Moved these terms to the left \"highlight_green%28+-375+%29\"
It becomes \"6%2Ax%2B15-highlight_green%28+375+%29=0\".
\n" ); document.write( "
Look at \"6%2Ax%2Bhighlight_red%28+15+%29-highlight_red%28+375+%29=0\".
Added fractions or integers together
It becomes \"6%2Ax%2Bhighlight_green%28+-360+%29=0\".
\n" ); document.write( "
Look at \"6%2Ax%2Bhighlight_red%28+-360+%29=0\".
Removed extra sign in front of \"-360\"
It becomes \"6%2Ax-highlight_green%28+360+%29=0\".
\n" ); document.write( "
Look at \"highlight_red%28+6%2Ax-360+%29=0\".
Solved linear equation \"highlight_red%28+6%2Ax-360=0+%29\" equivalent to 6*x-360 =0
It becomes \"highlight_green%28+0+%29=0\".
Result: \"0=0\"
\n" ); document.write( "This is an equation! Solutions: x=60.

Universal Simplifier and Solver

\n" ); document.write( "
Done!

\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 6. Based on the above results when x=60, then distance traveled by one bus is 3x=180 miles and the other bus traveled 3(x+5)=195 miles. Adding the two distances yield that they are 375 miles part.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 7. ANSWER: One bus traveled 180 miles and the other traveled 195 miles.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful. \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "And good luck in your studies!\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J
\n" ); document.write( "
\n" ); document.write( "
\n" );