document.write( "Question 214085: Some 5% alcohol Solution is mixed with another 20% alcohol solution to get a mixture of 25 liters of 14% solution. Find the amount of each alcohol solution before mixing. \n" ); document.write( "
Algebra.Com's Answer #161696 by nerdybill(7384)\"\" \"About 
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Some 5% alcohol Solution is mixed with another 20% alcohol solution to get a mixture of 25 liters of 14% solution. Find the amount of each alcohol solution before mixing.
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\n" ); document.write( "Let x = amount of 5% solution
\n" ); document.write( "then because the total mixture is 25 liters we have
\n" ); document.write( "25-x = amount of 20% solution
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\n" ); document.write( "Our equation:
\n" ); document.write( ".05x + .20(25-x) = .14(25)
\n" ); document.write( ".05x + 5 - .20x = 3.5
\n" ); document.write( "5 - .15x = 3.5
\n" ); document.write( "-.15x = -1.5
\n" ); document.write( "x = 10 liters (5% alcohol solution)
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\n" ); document.write( "20% alcohol solution:
\n" ); document.write( "25-x = 25-10 = 15 liters\r
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