document.write( "Question 213996: Please help me solve the substituation x+y=12 and x-y=-4. I can't figure out how to solve these \n" ); document.write( "
Algebra.Com's Answer #161640 by drj(1380)\"\" \"About 
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Please help me solve the substitution x+y=12 and x-y=-4. I can't figure out how to solve these.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2By=12\"
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\n" ); document.write( "\n" ); document.write( "The following will solve the system of linear equations by substitution.\r
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Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
\n" ); document.write( " \"+system%28+%0D%0A++++1%5Cx+%2B+1%5Cy+=+12%2C%0D%0A++++1%5Cx+%2B+-1%5Cy+=+4+%29%0D%0A++\"We'll use substitution. After moving 1*y to the right, we get:
\n" ); document.write( " \"1%2Ax+=+12+-+1%2Ay\", or \"x+=+12%2F1+-+1%2Ay%2F1\". Substitute that
\n" ); document.write( " into another equation:
\n" ); document.write( " \"1%2A%2812%2F1+-+1%2Ay%2F1%29+%2B+-1%5Cy+=+4\" and simplify: So, we know that y=4. Since \"x+=+12%2F1+-+1%2Ay%2F1\", x=8.
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\n" ); document.write( " Answer: \"system%28+x=8%2C+y=4+%29\".
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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful. \r
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\n" ); document.write( "\n" ); document.write( "For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "And good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J
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