document.write( "Question 213985This question is from textbook
\n" ); document.write( ": kirra is two years older then reggie. reggie is six times as old as delia. the average of their ages is nine years and four months. how old is each of them? \n" ); document.write( "
Algebra.Com's Answer #161632 by drj(1380)\"\" \"About 
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Kirra is two years older then Reggie. Reggie is six times as old as Delia. the average of their ages is nine years and four months. how old is each of them?\r
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\n" ); document.write( "\n" ); document.write( "Step 1. Let x be the age of Delia. Let 6x be the age of Reggie. Let 6x+2 be the age of Kirra\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Let Average ages be A=\"9%2B1%2F3=28%2F3\" years where 4/12=1/3 (4 months = 1/3 year)\r
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\n" ); document.write( "\n" ); document.write( "Step 3. \"A=28%2F3=%28x%2B6x%2B6x%2B2%29%2F3\" or \r
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\n" ); document.write( "\n" ); document.write( "\"28=13x%2B2\" \r
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\n" ); document.write( "\n" ); document.write( "\"26=13x\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=2\" Delia's age. Then\r
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\n" ); document.write( "\n" ); document.write( "\"6x=12\" Reggie's age\r
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\n" ); document.write( "\n" ); document.write( "\"6x%2B2=14\" Kirra's age\r
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\n" ); document.write( "\n" ); document.write( "Step 4. ANSWER: Delia is 2 years old, Reggie is 12 years old and Kirra is 14 years old. \r
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\n" ); document.write( "\n" ); document.write( "As a check the average is \"%282%2B12%2B14%29%2F3=28%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful. \r
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\n" ); document.write( "\n" ); document.write( "For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "And good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J
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