document.write( "Question 213985This question is from textbook
\n" ); document.write( ": kirra is two years older then reggie. reggie is six times as old as delia. the average of their ages is nine years and four months. how old is each of them? \n" ); document.write( "

Algebra.Com's Answer #161631 by Earlsdon(6294) $\"\"$ $\"About$

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Let K = Kirra's age, R = Reggie's age, and D = Delia's age.
\n" ); document.write( " $\"%28K%2BR%2BD%29%2F3+=+9\"$ $\"1%2F3\"$
\n" ); document.write( "K = R+2 \"Kirra is two years older than Reggie.\" Rewrite as K = R-2
\n" ); document.write( "R = 6D \"Reggie is six times as old as Delia.\"
\n" ); document.write( "K+R+D can be expressed as:
\n" ); document.write( " $\"%28%286D-2%29%2B6D%2BD%29%2F3+=+9\"$ $\"1%2F3\"$ Simplify.
\n" ); document.write( " $\"%2813D%2B2%29%2F3+=+9\"$ $\"1%2F3\"$ Multiply both sides by 3.
\n" ); document.write( " $\"13D%2B2+=+28\"$ Subtract 2 from both sides.
\n" ); document.write( " $\"13D+=+26\"$ Divide by 13.
\n" ); document.write( " $\"D+=+2\"$
\n" ); document.write( " $\"R+=+6D\"$
\n" ); document.write( " $\"R+=+6%282%29\"$
\n" ); document.write( " $\"R+=+12\"$
\n" ); document.write( " $\"K+=+R%2B2\"$
\n" ); document.write( " $\"K+=+12%2B2\"$
\n" ); document.write( " $\"K+=+14\"$
\n" ); document.write( "Kirra is 14 years old, Reggie is 12 years old and Delia is 2 years old. \n" ); document.write( "

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