document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29356>Question 29356</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve my son's word problem.  The sum of two number is 63.  Three times the larger number is 14 more than two times the smaller number.  What are the numbers?  Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16157 by </B><A HREF=/tutors/aboutme.mpl?userid=askmemath><B>askmemath(368)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=askmemath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16157\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the 2 numbers = X and Y<BR>\n" );
document.write( "Given X+Y = 63<BR>\n" );
document.write( "Let the Larger Number = X<BR>\n" );
document.write( "3X = 2Y+14\r<BR>\n" );
document.write( "\n" );
document.write( "X+Y = 63<BR>\n" );
document.write( "multiply both sides with 3<BR>\n" );
document.write( "3X+3Y = 63*3<BR>\n" );
document.write( "But we already know that 3X = 2Y+14<BR>\n" );
document.write( "2Y+14+3Y= 189<BR>\n" );
document.write( "5y+14 = 189<BR>\n" );
document.write( "Subtracting 14 on both sides<BR>\n" );
document.write( "5Y = 189-14<BR>\n" );
document.write( "5Y = 175<BR>\n" );
document.write( "Dividing by 5 on both sides<BR>\n" );
document.write( "Y = 35<BR>\n" );
document.write( "X = 63-35 = 28\r<BR>\n" );
document.write( "\n" );
document.write( "Ok, I've looked at this a number of times and for the life of me I cannot figure out where I am wrong since X is supposed to be the larger number and yet I get the value of X smaller than Y. </SPAN>\n" );
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