document.write( "Question 213816: 2x +3y=6 \n" ); document.write( "
Algebra.Com's Answer #161528 by drj(1380)\"\" \"About 
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\"2x+%2B3y=6\"\r
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\n" ); document.write( "\n" ); document.write( "Here I assume you want to plot the line.\r
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\n" ); document.write( "\n" ); document.write( "Step 1. Let's put it in slope-intercept form y=mx+b where m is the slope and b is the y-intercepts\r
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\n" ); document.write( "\n" ); document.write( "\"2x+%2B3y=6\"\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Subtract -2x from both sides of equation.\r
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\n" ); document.write( "\n" ); document.write( "\"2x+%2B3y-2x=6-2z\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x+%2B3y-2x=6-2z\"\r
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\n" ); document.write( "\n" ); document.write( "\"3y=6-2x\"\r
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\n" ); document.write( "\n" ); document.write( "Step 3. Divide 3 to both sides of equation\r
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\n" ); document.write( "\n" ); document.write( "\"3y%2F3=%286-2x%29%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-2x%29%2B2\"\r
\n" ); document.write( "\n" ); document.write( "Step 4. So y=-2x/3+2 where slope m=-2/3 and y-intercept b=2.\r
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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"2+x+%2B+3+y+=+6\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+-2%2F3\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 6/2 = 3.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 6/3 = 2.
  • Slope is -2/3 = -0.666666666666667.
  • Equation in slope-intercept form: y=-0.666666666666667*x+2.
\"graph%28+500%2C+500%2C+3-8%2C+3%2B8%2C+2-8%2C+2%2B8%2C+-0.666666666666667%2Ax%2B2+%29+\"\n" ); document.write( "

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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful. \r
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\n" ); document.write( "And good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J\r
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