document.write( "Question 213770This question is from textbook Structure and Method Book 1
\n" ); document.write( ": An ultra light aircraft flies to a nearby town that is 20 miles away in 2/5 hour with a tail wind. It can fly back home again when fighting a head wind in 1/2 hour. Find the air speed of the ultra light aircraft and the wind speed. Check your answer \n" ); document.write( "
Algebra.Com's Answer #161499 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "20=R*.4
\n" ); document.write( "20=.4R
\n" ); document.write( "R=20/.4
\n" ); document.write( "R=50 MPH. WITH THE WIND.
\n" ); document.write( "20R=R*.5
\n" ); document.write( ".5R=20
\n" ); document.write( "R=20/.5
\n" ); document.write( "R=40 MPH. AGAINST THE WIND.
\n" ); document.write( "(50-40)/2=10/2=5 MPH IS THE SPEED OF THE WIND.
\n" ); document.write( "PROOF:
\n" ); document.write( "50-5=45 MPH SPEED OF THE ULTRA LIGHT.
\n" ); document.write( "40+5=45 MPH DITTO.
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