document.write( "Question 213770This question is from textbook Structure and Method Book 1
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document.write( ": An ultra light aircraft flies to a nearby town that is 20 miles away in 2/5 hour with a tail wind. It can fly back home again when fighting a head wind in 1/2 hour. Find the air speed of the ultra light aircraft and the wind speed. Check your answer \n" );
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Algebra.Com's Answer #161499 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "20=R*.4 \n" ); document.write( "20=.4R \n" ); document.write( "R=20/.4 \n" ); document.write( "R=50 MPH. WITH THE WIND. \n" ); document.write( "20R=R*.5 \n" ); document.write( ".5R=20 \n" ); document.write( "R=20/.5 \n" ); document.write( "R=40 MPH. AGAINST THE WIND. \n" ); document.write( "(50-40)/2=10/2=5 MPH IS THE SPEED OF THE WIND. \n" ); document.write( "PROOF: \n" ); document.write( "50-5=45 MPH SPEED OF THE ULTRA LIGHT. \n" ); document.write( "40+5=45 MPH DITTO. \n" ); document.write( " \n" ); document.write( " |