document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=213743>Question 213743</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Obtain the area of a triangular plastic sheet whose sides are 3.93m and 4.15m if the angle between them is 41degrees 30'. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #161469 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=161469\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sides are 3.93m and 4.15m.<BR>\n" );
document.write( "angle between them is 41 degrees 30 minutes.<BR>\n" );
document.write( "area of a triangle is 1/2 base times height<BR>\n" );
document.write( "you need to find the height of the triangle.<BR>\n" );
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document.write( "label your triangle ABC.<BR>\n" );
document.write( "A is the vertex of your angle.<BR>\n" );
document.write( "B is the other end of the 3.93 meter side.<BR>\n" );
document.write( "C is the other end of the 4.15 meter side.<BR>\n" );
document.write( "draw a line from B to side AC intersecting with side AC at a right angle.<BR>\n" );
document.write( "call that intersection D.<BR>\n" );
document.write( "your triangle is now:<BR>\n" );
document.write( "ABC plus BD intersecting with AC at point D.<BR>\n" );
document.write( "your angle is angle A which is formed by sides AB and AD.  The angle is otherwise known as angle BAD.<BR>\n" );
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document.write( "you need to convert your angle into degrees.<BR>\n" );
document.write( "angle BAD = 41 degrees 30 minutes.<BR>\n" );
document.write( "30 minutes = 30/60 degrees = .5<BR>\n" );
document.write( "add .5 to 41 degrees and your angle becomes 41.5 degrees.<BR>\n" );
document.write( "angle BAD is now converted to degrees.<BR>\n" );
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document.write( "you may find the length of side BD by taking the sine of angle BAD.<BR>\n" );
document.write( "sine of angle BAD = opposite / hypotenuse.<BR>\n" );
document.write( "BD = opposite<BR>\n" );
document.write( "AB = hypotenuse<BR>\n" );
document.write( "sin(BAD) = BD / AB<BR>\n" );
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document.write( "solve for BD to get:<BR>\n" );
document.write( "BD = sin(BAD) * AB<BR>\n" );
document.write( "This becomes:<BR>\n" );
document.write( "BD = .662620048 * 3.93 = 2.604096789 meters.<BR>\n" );
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document.write( "you now have enough information to calculate the area of the triangle.<BR>\n" );
document.write( "area of a triangle = (base * height)/2.<BR>\n" );
document.write( "base of the triangle = AC = 4.15 meters.<BR>\n" );
document.write( "height of the triangle = BD = 2.604096789 meters<BR>\n" );
document.write( "area of the triangle = (AC * BD )/2 = (4.15 * 2.604096789)/2 = 5.403500838 meters.<BR>\n" );
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document.write( "Now that you are finished with all your calculations, you can round this to 5.4 square meters.<BR>\n" );
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document.write( "A picture of your triangle can be found at the following website:<BR>\n" );
document.write( "http://theo.x10hosting.com/<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Click on problem number 213743.<BR>\n" );
document.write( "If it's not there when you look, wait 30 minutes and try again.  It will be there.<BR>\n" );
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