document.write( "Question 213735: solve algebraically, using one variable. find three consecutive intergers such that three times the sum of the first two intergers is three less than seven times the third. \n" ); document.write( "
Algebra.Com's Answer #161462 by jim_thompson5910(35256)\"\" \"About 
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Recall that consecutive integers are of the form: x, x+1, x+2, x+3, etc...\r
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\n" ); document.write( "\n" ); document.write( "The statement: \"three times the sum of the first two intergers is three less than seven times the third\" translates to \"3%28x%2B%28x%2B1%29%29=7%28x%2B2%29-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%2B%28x%2B1%29%29=7%28x%2B2%29-3\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%2Bx%2B1%29=7%28x%2B2%29-3\" Remove unneeded parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"3%282x%2B1%29=7%28x%2B2%29-3\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"6x%2B3=7x%2B14-3\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"6x%2B3=7x%2B11\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"6x=7x%2B11-3\" Subtract \"3\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"6x-7x=11-3\" Subtract \"7x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-x=11-3\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-x=8\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%288%29%2F%28-1%29\" Divide both sides by \"-1\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=-8\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=-8\" \r
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\n" ); document.write( "\n" ); document.write( "This means that the three numbers are -8, -7, and -6\r
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