document.write( "Question 213617: Suppose that a rectangle has a perimeter of 22 meters.
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Algebra.Com's Answer #161402 by RAY100(1637)\"\" \"About 
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Perimeter = 2Length + 2 Width =22 (given)
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\n" ); document.write( "divide by 2 thruout,,,,L + W = 11,,,or L=11-W
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\n" ); document.write( "Area = Length * Width,,,,,,if we let w=x, and substitute
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\n" ); document.write( "A=(11-W) * (W) = (11-x) *(x) = 11x -x^2
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\n" ); document.write( "or,,,,A= 11x-x^2
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\n" ); document.write( "check,,,let L=10,,W=1,,,Per = 2(10)+ 2(1) = 22,,,,ok
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\n" ); document.write( "A=1*10=10,,,,,,A= 11(1)-(1)^2 = 10,,,,ok
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\n" ); document.write( "For L=9...w=2,,,,per =22 ok,,,,,A=9*2=18,,,A= 11(2)-2^ = 18,,,ok
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