document.write( "Question 213597: what is the answer to this problem? i have gotten stuck.
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document.write( "the square root of two thirds and the square root of three fourths.
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document.write( "sorry i forgot to say i needed it simplified.
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document.write( "studying for a chapter test tomorrow. \n" );
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Algebra.Com's Answer #161393 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! sqrt (2/3),,,,,,,sqrt (3/4) \n" ); document.write( ". \n" ); document.write( "to simplify (reduce) we factor, but with perfect squares(1,4,9,16,25,36,49,etc) \n" ); document.write( ". \n" ); document.write( "Let's do sqrt (3/4) first,,, \n" ); document.write( ". \n" ); document.write( "This also equals ,,,,(sqrt 3)/ (sqrt 4),,,, \n" ); document.write( ". \n" ); document.write( "the sqrt of 3 has only 1 as a potential factor, and this does not help\r \n" ); document.write( "\n" ); document.write( "The sqrt of 4 has 4 as a perfect square (2*2), and can be simplified \n" ); document.write( ". \n" ); document.write( "To (sqrt 3)/ (2),,, (just 2,, no sqrt),,,so \n" ); document.write( ". \n" ); document.write( "sqrt(3/4) = (sqrt 3) /2 = (1/2) sqrt 3 \n" ); document.write( ". \n" ); document.write( "checking with a calc, sqrt(3/4) = .866,,,,1/2 sqrt3=.866,,,,ok \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "Returning to sqrt(2/3), there are no perfect square factors that will help, so this is in simplified form already. \n" ); document.write( ". \n" ); document.write( "sqrt(2/3) = sqrt .667 = .816 \n" ); document.write( ". \n" ); document.write( "a Better example might be sqrt50 = sqrt(25*2)= sqrt25 * sqrt2= 5sqrt2 \n" ); document.write( ". \n" ); document.write( "or sqrt 200 = sqrt(100*2) = sqrt(100) * sqrt2 = 10sqrt2 \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |