document.write( "Question 213537: The length of a rectangle is four less than twice the width. The perimeter is 46 inches. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #161324 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=2W-4 \n" ); document.write( "P=2L+2W \n" ); document.write( "46=2(2W-4)+2W \n" ); document.write( "46=4W-8+2W \n" ); document.write( "46+8=6W \n" ); document.write( "54=6W \n" ); document.write( "W=54/6 \n" ); document.write( "W=9 FOR THE WIDTH. \n" ); document.write( "L=2*9-4 \n" ); document.write( "L=18-4 \n" ); document.write( "L=14 FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "46=2*14+2*9 \n" ); document.write( "46=28+18 \n" ); document.write( "46=46 \n" ); document.write( " \n" ); document.write( " |