document.write( "Question 213537: The length of a rectangle is four less than twice the width. The perimeter is 46 inches. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #161324 by checkley77(12844)\"\" \"About 
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L=2W-4
\n" ); document.write( "P=2L+2W
\n" ); document.write( "46=2(2W-4)+2W
\n" ); document.write( "46=4W-8+2W
\n" ); document.write( "46+8=6W
\n" ); document.write( "54=6W
\n" ); document.write( "W=54/6
\n" ); document.write( "W=9 FOR THE WIDTH.
\n" ); document.write( "L=2*9-4
\n" ); document.write( "L=18-4
\n" ); document.write( "L=14 FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "46=2*14+2*9
\n" ); document.write( "46=28+18
\n" ); document.write( "46=46
\n" ); document.write( "
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