document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29341>Question 29341</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A reduction of 10% in the price of tea enables a dealer to purchage 25kg more tea for Rs 22500.What is the reduced price per kg of tea? What was the original price per kg? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16131 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16131\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p = original price of tea in Rs/kg<BR>\n" );
document.write( ".1p = the reduction in the price of tea in Rs/gk<BR>\n" );
document.write( "p - .1p = the REDUCED price of tea in Rs/kg<BR>\n" );
document.write( "p - .1p = (1 - .1)p = .9p<BR>\n" );
document.write( "(.1p Rs/kg)(25 kg) = 22500 Rs<BR>\n" );
document.write( "2.5p Rs = 22500 Rs<BR>\n" );
document.write( "p = 9000 Rs/kg the original price<BR>\n" );
document.write( ".9p = 8100 Rs/kg the reduced price </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );