document.write( "Question 213488: I am still unsure when it comes to functions. I have a question that is as follows: Is f(x) = x^2 + 2x - 3 a one-to-one function? Explain your answer.\r
\n" ); document.write( "\n" ); document.write( "When figuring out the problem if f(a) = f(b) then my answer would be no as
\n" ); document.write( "a^2 + 2a - 3 = b^2 + 2b -3 does not factor down to a = b.\r
\n" ); document.write( "\n" ); document.write( "Am I figuring this correctly?\r
\n" ); document.write( "\n" ); document.write( "Thank you = Lori
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Algebra.Com's Answer #161291 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You're on the right track. A function is one-to-one if \"f%28a%29=f%28b%29\" only means \"a=b\". In other words, if two outputs of a function are equal, then the inputs must be equal for the function to be one-to-one.\r
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\n" ); document.write( "\n" ); document.write( "So if you think that this function is NOT one-to-one, then simply pick a counter-example to prove this claim false. Let's say that \"f%28a%29=f%28b%29=-3\". Plugging this into \"f%28x%29=x%5E2%2B2x-3\" gets us \"-3=x%5E2%2B2x-3\". Now solve for 'x' to get \"x=0\" or \"x=-2\"\r
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\n" ); document.write( "\n" ); document.write( "So if we plug in either 0 or -2 into f(x), we'll get -3 as an output. Ie. \"f%280%29=f%28-2%29=-3\". Since \"0%3C%3E-2\", this means that the function is NOT one-to-one. So you are correct.\r
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