document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=213485>Question 213485</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if 2t+(s-r)/3= t what is s in terms of r and t? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #161282 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=161282\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> equation is 2t + (s-r)/3 = t<BR>\n" );
document.write( "solve for s.<BR>\n" );
document.write( "multiply both sides of the equation by 3 to get:<BR>\n" );
document.write( "2*3*t + s - r = 3*t<BR>\n" );
document.write( "add r and subtract 2*3*t  from both sides of the equation to get:<BR>\n" );
document.write( "s = 3*t - 2*3*t + r<BR>\n" );
document.write( "this becomes:<BR>\n" );
document.write( "s = 3t - 6t + r which becomes:<BR>\n" );
document.write( "s = -3t + r<BR>\n" );
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document.write( "if you let t = 1 and r = 1, you get s = -3 + 1 = -2<BR>\n" );
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document.write( "if you substitute s = -2 and t = 1 and r = 1 into the original equation you get:<BR>\n" );
document.write( "2t + (s-r)/3 = t becoming:<BR>\n" );
document.write( "2 + (-2-1)/3 = 1 which becomes:<BR>\n" );
document.write( "2 -(3/3) = 1 which becomes:<BR>\n" );
document.write( "1 = 1 which is true so the value for s is good.<BR>\n" );
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document.write( "your answer is:<BR>\n" );
document.write( "s = -3t + r<BR>\n" );
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document.write( " </SPAN>\n" );
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