document.write( "Question 213455: what is the vertex of parabola y=8x+1-4x^2? I need all the steps so I can understand the solution.\r
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Algebra.Com's Answer #161236 by stanbon(75887)\"\" \"About 
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what is the vertex of parabola y=8x+1-4x^2? I need all the steps so I can understand the solution
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\n" ); document.write( "a = -4, b = 8, c = 1
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\n" ); document.write( "Vertex occurs at x = -b/2a = -8/(2*-4) = 1
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\n" ); document.write( "f(1) = 8 + 1 - 4 = 5
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\n" ); document.write( "Vertex: (1,5)
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\n" ); document.write( "If you work it by completing the square you get:
\n" ); document.write( "-4x^2 + 8x + ? = y - 1 + ?
\n" ); document.write( "-4(x^2 - 2x + (-1)^2) = y - 1 + -4*1
\n" ); document.write( "-4(x - 1)^2 = y-5
\n" ); document.write( "From this you can see that h=1 and k = 5
\n" ); document.write( "So vertex is at (1,5)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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