document.write( "Question 29327: A wife and husband, Linda and Mark, have ages that total 80 years. Two years ago, 2 times Mark's age was 2 years more than 3 times Linda's age. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #16122 by sdmmadam@yahoo.com(530)\"\" \"About 
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A wife and husband, Linda and Mark, have ages that total 80 years. Two years ago, 2 times Mark's age was 2 years more than 3 times Linda's age. How old is each now?
\n" ); document.write( "Let Linda's age be L years
\n" ); document.write( "and let Mark's age be M year.
\n" ); document.write( "Linda and Mark, have ages that total 80 years.
\n" ); document.write( "That is L+M = 80 ---(1)
\n" ); document.write( "Two years ago Linda was (L-2) years old
\n" ); document.write( "and Mark was (m-2)years old
\n" ); document.write( "Then 2 times Mark's age was 5 years more than 3 times Linda's age
\n" ); document.write( "That is 2(M-2)= 3(L-2)+2 ----(2)
\n" ); document.write( "That is 2M-4=3L-6+2
\n" ); document.write( "2M-3L= 4-6+2
\n" ); document.write( "2M-3L= 0 ----(*)
\n" ); document.write( "using (1) and substituting for L=(80-M)in (*)
\n" ); document.write( " 2M-3(80-M) =0
\n" ); document.write( "2M-240-3M= 0
\n" ); document.write( "2M+3M= 240
\n" ); document.write( "5M=240
\n" ); document.write( "M= 240/5 = 48
\n" ); document.write( "L= 80 - 48 = 32
\n" ); document.write( "Answer: Mark is now 48 years old and Linda is 32 years old
\n" ); document.write( "Verification: Two years ago,M= (48-2) = 46 and L= (32-2) = 30
\n" ); document.write( "Twice (46) should be 2 more than thrice(30)
\n" ); document.write( "that is 92 should be 2 more than 90 which is so
\n" ); document.write( "Hence their ages are correct. \n" ); document.write( "
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