document.write( "Question 213427This question is from textbook PRECALCULUS
\n" ); document.write( ": WHAT TYPE OF FORMULA AM I SUPPOSE TO USE IN ORDER TO FIND THE VALUE OF X 0R Y. THE DIRECTIONS SAY, \"FIND THE VALUE OF X OR Y SO THAT THE LINE THROUGH THE PAIR OF POINTS HAS THE GIVEN SLOPE.\" I'M NOT SURE HOW TO DO THAT. THE GIVEN IS (-2,3) AND (4,y) with the slope of -3. \n" ); document.write( "
Algebra.Com's Answer #161206 by ankor@dixie-net.com(22740)\"\" \"About 
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WHAT TYPE OF FORMULA AM I SUPPOSE TO USE IN ORDER TO FIND THE VALUE OF X 0R Y. THE DIRECTIONS SAY, \"FIND THE VALUE OF X OR Y SO THAT THE LINE THROUGH THE PAIR OF POINTS HAS THE GIVEN SLOPE.\" I'M NOT SURE HOW TO DO THAT. THE GIVEN IS (-2,3) AND (4,y) with the slope of -3.
\n" ); document.write( ":
\n" ); document.write( "Use the slope formula to find y: that is \"%28y2-y1%29%2F%28x2-x1%29\" = m
\n" ); document.write( "Assign the given values as follows:
\n" ); document.write( "x1=-2; y1=3
\n" ); document.write( "x2 =4; y2= y
\n" ); document.write( "m = -3
\n" ); document.write( ":
\n" ); document.write( "Substitute the given values as follows and find y
\n" ); document.write( "\"%28y-3%29%2F%284-%28-2%29%29\" = -3
\n" ); document.write( "\"%28y-3%29%2F%284%2B2%29\" = -3
\n" ); document.write( "\"%28y-3%29%2F6\" = -3
\n" ); document.write( "Multiply both sides by 6
\n" ); document.write( "y - 3 = 6(-3)
\n" ); document.write( "y = -18 + 3
\n" ); document.write( "y = -15; the pair is: 4,-15
\n" ); document.write( ";
\n" ); document.write( "Use the point/slope formula to find the equation
\n" ); document.write( "y - y1 = m(x - x1)
\n" ); document.write( "Substitute the given values
\n" ); document.write( "y - 3 = -3(x -(-2))
\n" ); document.write( "y - 3 = -3(x + 2)
\n" ); document.write( "y - 3 = -3x - 6
\n" ); document.write( "y = -3x - 6 + 3
\n" ); document.write( "y = -3x - 3 is the equation
\n" ); document.write( ":
\n" ); document.write( "Check solution by substituting the x value of 4
\n" ); document.write( "y = -3(4) - 3
\n" ); document.write( "y = = -12 - 3
\n" ); document.write( "y = -15 which is the value we got for y
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