document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=213158>Question 213158</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given the function f is defined by f(x)= ax^2 + bx + c Given that f(0) = 6, f(-1)= 15, and f(1) = 1, find the values of a, b, and c. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #161202 by </B><A HREF=/tutors/aboutme.mpl?userid=shymeerab><B>shymeerab(21)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=shymeerab><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=161202\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x)=ax^2+bx+c<BR>\n" );
document.write( "for x=0<BR>\n" );
document.write( "f(0)=c  as given f(0)=6 so c=6<BR>\n" );
document.write( "for x=-1<BR>\n" );
document.write( "f(-1)=a-b+6  as given f(-1)=15 so a-b+6=15; a-b=9 _____e<BR>\n" );
document.write( "for x=1<BR>\n" );
document.write( "f(1)=a+b+6 as given f(1)=1 so a+b+6=1; a+b=-5 _____f<BR>\n" );
document.write( "by adding eq e & f  we have a=2<BR>\n" );
document.write( "and put value of 'a' in eq f we have b=-7 so we have<BR>\n" );
document.write( "a=2;b=-7;c=6   \r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );