document.write( "Question 3630: what is the equation form passing through lines (1,3)and (-1,2) \n" ); document.write( "
Algebra.Com's Answer #1612 by AnlytcPhil(1810)\"\" \"About 
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\n" ); document.write( ">>...What is the equation form passing through lines (1,3) and (-1,2)...<<
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\n" ); document.write( "The equation of the line passing through two points (x1,y1) and (x2,y2)
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\n" ); document.write( "` ` `y - y1 = m(x - x1)
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\n" ); document.write( "where
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\n" ); document.write( "` ` ` ` ` y2 - y1
\n" ); document.write( "` ` `m = —————————
\n" ); document.write( "` ` ` ` ` x2 - x1
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\n" ); document.write( "In this case (x1,y1) = (1,3) and (x2,y2) = (-1,2)
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\n" ); document.write( "First substitute in the formula for m:
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\n" ); document.write( "` ` ` ` ` y2 - y1
\n" ); document.write( "` ` `m = —————————
\n" ); document.write( "` ` ` ` ` x2 - x1
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\n" ); document.write( "` ` ` ` ` (2) - (3)
\n" ); document.write( "` ` `m = ———————————
\n" ); document.write( "` ` ` ` `(-1) - (1)
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\n" ); document.write( "` ` ` ` `-1` ` `1
\n" ); document.write( "` ` `m = ——— = ———
\n" ); document.write( "` ` ` ` `-2` ` `2
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\n" ); document.write( "Now substitute 1/2 for m, 1 for x1, 3 for y1, -1 for x2 and 3 for y2
\n" ); document.write( "in the formula
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\n" ); document.write( "` ` `y - y1 = m(x - x1)
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\n" ); document.write( "` ` ` y - 3 = (1/2)(x - 1)
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\n" ); document.write( "Now clear of fractions by multiplying both side by 2
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\n" ); document.write( "` `2[y - 3] = 2[(1/2)(x - 1]
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\n" ); document.write( "` `2[y - 3] = 2[1/2)(x - 1]
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\n" ); document.write( "` ` `2y - 6 = x - 1
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\n" ); document.write( "The standard form is to have the x-term first, then the y-term,
\n" ); document.write( "then an equal sign and then a number:
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\n" ); document.write( "` ` `-x + 2y = 6 - 1
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\n" ); document.write( "` ` `-x + 2y = 5
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\n" ); document.write( "The standard form is considered best when the x-term is positive,
\n" ); document.write( "so multiply through by -1
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\n" ); document.write( "` ` ` `x - 2y = -5
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\n" ); document.write( "Edwin J
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