document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29328>Question 29328</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A wife and husband, Linda and Mark, have ages that total 80 years. Two years ago, 2 times Mark's age was 2 years more than 3 times Linda's age. How old is each now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16119 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16119\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let Linda's age be x<BR>\n" );
document.write( "Let Mark's age be y<BR>\n" );
document.write( "x+y=80 (solve for y)<BR>\n" );
document.write( "y=80-x (subitution)\r<BR>\n" );
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document.write( "Two years ago Mark's age  = y-2<BR>\n" );
document.write( "Two years ago Linda's age = x-2\r<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "3(x-2)+2=2(y-2)<BR>\n" );
document.write( "3x-6+2=2y-4<BR>\n" );
document.write( "Subsitue for y<BR>\n" );
document.write( "3x-4=2(80-x)-4<BR>\n" );
document.write( "3x-4=160-2x-4<BR>\n" );
document.write( "5x=160<BR>\n" );
document.write( "x=32\r<BR>\n" );
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document.write( "y=80-32<BR>\n" );
document.write( "y=48\r<BR>\n" );
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document.write( "Hence, Linda is 32 years old and Mark is 48 years old.<BR>\n" );
document.write( "PAul.<BR>\n" );
document.write( " </SPAN>\n" );
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