document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=213396>Question 213396</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780131349568/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A gardener has 46 ft of fencing to be used to enclose a rectangular garden that has a border 2 feet wide surrounding it.<BR>\n" );
document.write( "If the length of the garden is twice its width what will be the dimensions of the garden? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #161188 by </B><A HREF=/tutors/aboutme.mpl?userid=drj><B>drj(1380)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drj><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=drj><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=161188\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A gardener has 46 ft of fencing to be used to enclose a rectangular garden that has a border 2 feet wide surrounding it.  If the length of the garden is twice its width what will be the dimensions of the garden?\r<BR>\n" );
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document.write( "Step 1.  Let L=2w be the length of garden and let w garden\r<BR>\n" );
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document.write( "Step 2.  Let L+2 and w+2 include the border\r<BR>\n" );
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document.write( "Step 3.  Let P = 46  ft be the perimeter.  Perimeter means adding the 4 sides of a rectangle.  So,\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P=L%2B2%2BL%2B2%2Bw%2B2%2Bw%2B2=2L%2B2w%2B8=2%282w%29%2B2w%2B8=6w%2B8 ALIGN=MIDDLE  ALT=\"P=L%2B2%2BL%2B2%2Bw%2B2%2Bw%2B2=2L%2B2w%2B8=2%282w%29%2B2w%2B8=6w%2B8\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P=46=6w%2B8 ALIGN=MIDDLE  ALT=\"P=46=6w%2B8\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Step 3.  Subtract 8 from both sides of equation\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=46-8=6w%2B8-8 ALIGN=MIDDLE  ALT=\"46-8=6w%2B8-8\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=38=6w ALIGN=MIDDLE  ALT=\"38=6w\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Step 4.  Divide 6 to both sides of equation to get w by itself\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=38%2F6=6w%2F6 ALIGN=MIDDLE  ALT=\"38%2F6=6w%2F6\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=w=19%2F3 ALIGN=MIDDLE  ALT=\"w=19%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Step 5.  w = 19/3 is the width of the rectangle and length L is 38/3  since <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=L=2w%29 ALIGN=MIDDLE  ALT=\"L=2w%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.   With the border w+2=25/3 and 2w+2=44/3  \r<BR>\n" );
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document.write( "Check P=6w+8= 6*(19/3)+8= 46 So w = 25/3 ft and L=44/3 is the solution.\r<BR>\n" );
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document.write( "Hope the above steps were helpful.  Good luck in your homework and studies!  \r<BR>\n" );
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document.write( "Respectfully<BR>\n" );
document.write( "Dr J\r<BR>\n" );
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document.write( "Hope you understood and followed the steps. Good luck in your studies. Dr J \r<BR>\n" );
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document.write( "For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trig Vids please visit http://www.FreedomUniversity.TV/courses/Trigonometry </SPAN>\n" );
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