document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=213360>Question 213360</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A sample of copper with a mass of 63.5g contains 6.02X10^23 atoms. Calculate the mass of a single copper atom. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #161181 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=161181\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> mass  of  63.5 g = 6.02x10^23 atoms <BR>\n" );
document.write( ".<BR>\n" );
document.write( "to  find x g = 1 atom ,,,,,,,divide  both  sides  of  original  eqn  by  6,02 x 10^23<BR>\n" );
document.write( ".<BR>\n" );
document.write( "63.5 g / 6.02x10^23 = 1.0548 x 10^-22 g = 6.02 x10^23/6.02 x 10^23 = 1 atom<BR>\n" );
document.write( ".<BR>\n" );
document.write( "answer  is one  atom  has  mass  of  1.0548 x 10^-22 g<BR>\n" );
document.write( ".<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );