document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=213295>Question 213295</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780495565215/algebrahomeworkh>College  Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I am really having a hard time setting this equation up, please help, show steps to answer for future use.\r<BR>\n" );
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document.write( "A salesman drives from Ajax to Barrington, a distance of 120 mi. at a steady speed.  He then increases his speed by 10 mi/h to drive the 150 mi from Barrington to Collins.  If the second leg of his trip took 6 min. more time then the first leg, how fast was he driving between Ajax and Barrington?\r<BR>\n" );
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document.write( "All help is greatly appreciated!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #161130 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=161130\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A salesman drives from Ajax to Barrington, a distance of 120 mi. at a steady speed. He then increases his speed by 10 mi/h to drive the 150 mi from Barrington to Collins. If the second leg of his trip took 6 min. more time then the first leg, how fast was he driving between Ajax and Barrington? <BR>\n" );
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document.write( "A to B DATA:<BR>\n" );
document.write( "distance = 120 miles ; rate = r mph ; time = d/r = 120/r hrs.<BR>\n" );
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document.write( "B to C DATA:<BR>\n" );
document.write( "distance = 150 miles ; rate = (r+10) mph ; time = 150/(r+10) hrs.<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "B to C time - A to B time = 1/10 hr<BR>\n" );
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document.write( "150/(r+10) - 120/r = 1/10<BR>\n" );
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document.write( "Multiply thru by 10r(r+10) to get:<BR>\n" );
document.write( "1500r - 1200(r+10) = r(r+10)<BR>\n" );
document.write( "300r - 12000 = r^2 + 10r<BR>\n" );
document.write( "r^2 - 290r + 12000 = 0<BR>\n" );
document.write( "(r-50)(r-240) = 0<BR>\n" );
document.write( "Realistic solution:<BR>\n" );
document.write( "r = 50 mph (His rate from A to B)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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