document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=213292>Question 213292</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 4% acid solution should be mixed with 30 gallons of a 13% acid solution to obtain a mixture that is 7% acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #161119 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=161119\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .13x+.04*30=.07(30+x)<BR>\n" );
document.write( ".13x+1.2=2.1+.07x<BR>\n" );
document.write( ".13x-.07x=2.1-1.2<BR>\n" );
document.write( ".06x=.9<BR>\n" );
document.write( "x=.9/.06<BR>\n" );
document.write( "x=15 gallons of 13% acid is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".13*15+.04*30=.07(30+15)<BR>\n" );
document.write( "1.95+1.2=.07*45<BR>\n" );
document.write( "3.15=3.15\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );