document.write( "Question 213177: Ben is one more than two times as old as Denise. In 19 years the sum of their ages will be 126. How old is Ben now? \n" ); document.write( "
Algebra.Com's Answer #161081 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! Ben is one more than two times as old as Denise. In 19 years the sum of their ages will be 126. How old is Ben now?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let Denise's current age be D\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since Ben's age is one more than 2 times Denise's age, then Ben's current age is 2D + 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In 19 years, Denise will be D + 19, and Ben will be (2D + 1 + 19), or 2D + 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since in 19 years, their ages will total 126, then we'll have:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "D + 19 + 2D + 20 = 126\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3D + 39 = 126\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3D = 87\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, Ben is currently |