document.write( "Question 29309: Solve for x:
\n" ); document.write( "log(base10)8 - 1/3log(base10)x = log(base10)2\r
\n" ); document.write( "\n" ); document.write( "I would really appreciate your help for this problem,
\n" ); document.write( "Thank You so much.
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Algebra.Com's Answer #16104 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve for x: All logs are to the base 10.
\n" ); document.write( "\"log%288%29-%281%2F3%29log%28x%29+=+log%282%29\" Add\"%281%2F3%29log%28x%29\" to both sides of the equation.
\n" ); document.write( "\"log%288%29+=+%281%2F3%29log%28x%29+%2B+log%282%29\" Subtract \"log%282%29\" from both sides.
\n" ); document.write( "\"log%288%29-log%282%29+=+%281%2F3%29log%28x%29\" Apply the \"quotient rule\" for logarithms to the left side.
\n" ); document.write( "\"log%288%2F4%29+=+%281%2F3%29log%28x%29\"
\n" ); document.write( "\"log%284%29+=+%281%2F3%29log%28x%29\" Multiply both sides by 3.
\n" ); document.write( "\"3log%284%29+=+log%28x%29\"
\n" ); document.write( "\"log%284%5E3%29+=+log%28x%29\"
\n" ); document.write( "\"4%5E3+=+x\"
\n" ); document.write( "\"x+=+64\"
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