document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=213139>Question 213139</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (6x-60)=(3x+30) can u help me with this Please  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #161031 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=161031\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6x-60=3x+30,,,,,add  60  to  both  sides<BR>\n" );
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document.write( "6x = 3x +90,,,,,subtract  3x  from  both  sides<BR>\n" );
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document.write( "3x = 90,,,,,,divide  both  sides  by  3<BR>\n" );
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document.write( "x=90/3 = 30<BR>\n" );
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document.write( "check,,6(30) -60 = 3(30) +30<BR>\n" );
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document.write( "180-60 = 90+30<BR>\n" );
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document.write( "120 = 120<BR>\n" );
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