document.write( "Question 213122: the average speed of a car increases from 60km/h-70 km/h, the time needed to cover a certain distance decreases by 30 minutes. what is the distance involved? \n" ); document.write( "
Algebra.Com's Answer #161007 by jonvaliente(64)\"\" \"About 
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Since: Speed=Distance/Time
\n" ); document.write( "And Time = Distance/Speed
\n" ); document.write( "The distance did not change and we let this value be D
\n" ); document.write( "When Speed = 60, Time is T, as in:
\n" ); document.write( "...
\n" ); document.write( "\"T+=+D%2F60\"
\n" ); document.write( "...
\n" ); document.write( "When Speed = 70, Time is T-30 minutes(30 minutes is half an hour, speed is expressed as km/h) so, T-0.5, as in:
\n" ); document.write( "\"T-0.5+=+D%2F70+\"
\n" ); document.write( "...
\n" ); document.write( "Substituting the value of T from the first equation, we get:
\n" ); document.write( "\"%28D%2F60%29-0.5+=+D%2F70\"
\n" ); document.write( "\"%28D%2F60%29-%28D%2F70%29+=+0.5\"
\n" ); document.write( "Getting the LCD, 420 we get:
\n" ); document.write( "\"%287D-6D%29%2F420=0.5\"
\n" ); document.write( "Multiplying both sides by 420 we get:
\n" ); document.write( "\"D+=+0.5%2A420+=+210+km\"
\n" ); document.write( "So the distance involved is 210km
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