document.write( "Question 213122: the average speed of a car increases from 60km/h-70 km/h, the time needed to cover a certain distance decreases by 30 minutes. what is the distance involved? \n" ); document.write( "
Algebra.Com's Answer #161007 by jonvaliente(64)![]() ![]() You can put this solution on YOUR website! Since: Speed=Distance/Time \n" ); document.write( "And Time = Distance/Speed \n" ); document.write( "The distance did not change and we let this value be D \n" ); document.write( "When Speed = 60, Time is T, as in: \n" ); document.write( "... \n" ); document.write( " \n" ); document.write( "... \n" ); document.write( "When Speed = 70, Time is T-30 minutes(30 minutes is half an hour, speed is expressed as km/h) so, T-0.5, as in: \n" ); document.write( " \n" ); document.write( "... \n" ); document.write( "Substituting the value of T from the first equation, we get: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Getting the LCD, 420 we get: \n" ); document.write( " \n" ); document.write( "Multiplying both sides by 420 we get: \n" ); document.write( " \n" ); document.write( "So the distance involved is 210km \n" ); document.write( " \n" ); document.write( " |