document.write( "Question 29299: I need help with solving the system of equations algebraically. The problem is : y=2x^2
\n" ); document.write( " y= x+3
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Algebra.Com's Answer #16095 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Try this:
\n" ); document.write( "\"y+=+2x%5E2\" and \"y+=+x%2B3\" Since y = y you can write:
\n" ); document.write( "\"2x%5E2+=+x%2B3\" Simplify.
\n" ); document.write( "\"2x%5E2-x-3+=+0\" Solve this quadratic by factoring.
\n" ); document.write( "\"%282x-3%29%28x%2B1%29+=+0\" Apply the zero products principle.
\n" ); document.write( "\"2x-3+=+0\" and/or \"x%2B1+=+0\"
\n" ); document.write( "If \"2x-3+=+0\" then \"2x+=+3\" and \"x+=+3%2F2\"
\n" ); document.write( "If \"x%2B1+=+0\" then \"x+=+-1\"\r
\n" ); document.write( "\n" ); document.write( "We have found the x-coordinates of the solutions. To find the y-coordinates, substitute the x-values into either of the original equations and solve for y.\r
\n" ); document.write( "\n" ); document.write( "\"x+=+3%2F2\" Substitute into \"y+=+x%2B3\"
\n" ); document.write( "\"y+=+3%2F2+%2B+3\"
\n" ); document.write( "\"y+=+3%2F2+%2B+6%2F2\"
\n" ); document.write( "\"y+=+9%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+-1\" Substitute into \"y+=+2x%5E2\"
\n" ); document.write( "\"y+=+2%28-1%29%5E2\"
\n" ); document.write( "\"y+=+2\"\r
\n" ); document.write( "\n" ); document.write( "The solutions are:
\n" ); document.write( "(3/2, 9/2) and (-1, 2)\r
\n" ); document.write( "\n" ); document.write( "Why are there two solutions? Because you have a parabola \"y+=+2x%5E2\" transversed by a line \"y+=+x%2B3\"\r
\n" ); document.write( "\n" ); document.write( "Here's a graph showing the two intersections/solutions.
\n" ); document.write( "\"graph%28300%2C200%2C-5%2C5%2C-5%2C5%2C2x%5E2%2Cx%2B3%29\"
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