document.write( "Question 212993: If an object on Earth is projected upward with an initial velocity of 32 feet per second, then its height after (t) seconds is given by: h(t)=32t-16t^2. Find the maximum height attained by the object and the number of seconds it takes to hit the ground.\r
\n" ); document.write( "\n" ); document.write( "I began like this:
\n" ); document.write( "h(t)=-16t^2 + 32t
\n" ); document.write( "-32/2(-16)=-32/32=1
\n" ); document.write( "-16(1)^2 + 32(1)
\n" ); document.write( "-16+32=16 and now I am stuck! \n" ); document.write( "

Algebra.Com's Answer #160900 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
You're pretty much done. What you just did was find the vertex of $\"h%28t%29=-16t%5E2+%2B+32t\"$ . The vertex is (1,16) and at the vertex is the max value of h(t) (ie the height). So the max height is 16 ft (which occurs at t=1 second). \n" ); document.write( "

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